A particle performing S.H.M. has a velocity of 10 m/s, when it crosses the mean position. If the amplitude of oscillation is 2 m, then what is the velocity at midway between mean position and extreme position ?

A particle performing S.H.M. has a velocity of 10 m/s, when it crosses

1.	A particle performing S.H.M. has a velocity of 10 m/s, when it crosses the mean position. If the amplitude of oscillation is 2 m, then what is the velocity at midway between mean position and extreme position ?
Answer» SOLUTION :Velocity at MEAN position is maximum `v_max=aomega` `THEREFORE 10=2xxomega` ` therefore omega=5` v=omegasqrt(a^2-x^2) =5sqrt((2)^2-(1)^2)` `=5xxsqrt3 m//s.`

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A particle performing S.H.M. has a velocity of 10 m/s, when it crosses the mean position. If the amplitude of oscillation is 2 m, then what is the velocity at midway between mean position and extreme position ?

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