A particle performing S.H.M. has an acceleration of 100 cm/s^2, when it is at a distance of 25 cm from the mean position. Calculate the period of SHM.

A particle performing S.H.M. has an acceleration of 100 cm/s^2, when i

1.	A particle performing S.H.M. has an acceleration of 100 cm/s^2, when it is at a distance of 25 cm from the mean position. Calculate the period of SHM.
Answer» SOLUTION :"Acceleration"`=omega^2X=((2PI)/T)^2x` T^2=(4pi^2x)/(Ac c^n)= (4xx9.87xx25)/100=9.87` `therefore T=pi sec.`.

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A particle performing S.H.M. has an acceleration of 100 cm/s^2, when it is at a distance of 25 cm from the mean position. Calculate the period of SHM.

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