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A particle performs S.H.M. of amplitude 10 cm. Its maximum velocity during oscillations is 100 cm/s. What is its displacement when the velocity is 60 cm/s ? |
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Answer» SOLUTION :`v=omegasqrt(a^2-x^2)` `v^2=omega^2(a^2-x^2)=(v_max/a)^2(a^2-x^2)` `60^2=(100/10)^2(10^2-x^2)` `3600=100(100-x^2)` `thereforex=8cm` |
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