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A particle perfroming S.H.M. gas a period of 6 sec and its maximum velocity during the oscillation is 6.28 cm/sec. Find the time required by it to cover adistance of 3 cm from its mean position. |
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Answer» SOLUTION :`x=asinomegat=asin((2pit)/T)` `3=6sin((2pit)/6)1/2= SIN((2pit)/6)` `sin (pi/6)=sin((2pit)/6)` `pi/6=(2pit)/6 t=1/2sec.` |
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