A particle projected horizontally from the top of an inclined plane inclined at an angle theta with the horizontal with velocity u. What is the distance along the plane from the point of projection at which the projectile strikes the inclined plane ?

A particle projected horizontally from the top of an inclined plane in

1.	A particle projected horizontally from the top of an inclined plane inclined at an angle theta with the horizontal with velocity u. What is the distance along the plane from the point of projection at which the projectile strikes the inclined plane ?
Answer» `(2U^(2)TAN(THETA))/G` `1/2 (u^(2)tan(theta))/g` `(2u^(2)tan^(2)(theta))/g` `(2u^(2)tan(theta)SEC theta)/g` Answer :D

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A particle projected horizontally from the top of an inclined plane inclined at an angle theta with the horizontal with velocity u. What is the distance along the plane from the point of projection at which the projectile strikes the inclined plane ?

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