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A particle projected with velocity u at angle `theta` with horizontal at t=0. What is the magnitude of change in the velocity of the particle when it is at maximum height?A. `(u cos theta)/2`B. `u cos theta`C. `u sin theta`D. none of these |
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Answer» Correct Answer - c `vecu_(i)=u cos theta hati+u sin theta hatj` `vecu_(f)=u cos theta hati` `Deltavecu=vecu_(f)-vecu_(i)=-u sin thetahatj` `|Deltavecu|=u sin theta` |
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