A particle starts from rest and moves with a uniform acceleration of 5 m/s2 for 10 s and then it moves with a constant velocity for 4 s. Later it slows down and comes to rest in 5 s. Draw the velocity graph for the motion of the body and calculate the total distance travelled?

A particle starts from rest and moves with a uniform acceleration of 5

1.	A particle starts from rest and moves with a uniform acceleration of 5 m/s2 for 10 s and then it moves with a constant velocity for 4 s. Later it slows down and comes to rest in 5 s. Draw the velocity graph for the motion of the body and calculate the total distance travelled?
Answer» Distance TRAVELED in 5th SECOND = Distance traveled in 5 s− Distance traveled in 4 sDistance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 MDISTANCE traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S 1Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S 1Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S 1 =(62.5−40)m=22.5m

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A particle starts from rest and moves with a uniform acceleration of 5 m/s2 for 10 s and then it moves with a constant velocity for 4 s. Later it slows down and comes to rest in 5 s. Draw the velocity graph for the motion of the body and calculate the total distance travelled?

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