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A particle starts from rest in circular path of radius R = 2 m such that its angular velocity is omega = (pi t)/(3) rad/s. Find the magnitude of average velocity of particle when it has maoved by angle 60^(@) from its initial position. |
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Answer» `sqrt3 m//s` `omegta = (PI t)/(3) ` `alpha = ( d omega)/(dt) = (pi)/(3) rad //s^(2) ` `theta = (pi)/(3) =1/2 alpha t^(2)` `pi/3 =1/2 (pi//3) t^(2) ` `t = sqrt2s` Now displacement of paraticle is given as `d= R =2M` `V = (2)/(sqrt2) = 2sqrtm//s` 
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