A particle starts its motion from rest under the action of a constant force. If the distance covered in first `10 s` is `s_1` and the covered in the first `20 s` is `s_2`, then.A. `S_(2)=S_(1)`B. `S_(2)=2S_(1)`C. `S_(2)=3S_(1)`D. `S_(2)=4S_(1)`

A particle starts its motion from rest under the action of a constant

1.	A particle starts its motion from rest under the action of a constant force. If the distance covered in first `10 s` is `s_1` and the covered in the first `20 s` is `s_2`, then.A. `S_(2)=S_(1)`B. `S_(2)=2S_(1)`C. `S_(2)=3S_(1)`D. `S_(2)=4S_(1)`
Answer» Correct Answer - D `s=(1)/(2)at^(2)` ltbtgt `(s_(2))/(s_(1))=((20)/(10))^(2)=4` `s_(2)=4s_(1)`

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A particle starts its motion from rest under the action of a constant force. If the distance covered in first `10 s` is `s_1` and the covered in the first `20 s` is `s_2`, then.A. `S_(2)=S_(1)`B. `S_(2)=2S_(1)`C. `S_(2)=3S_(1)`D. `S_(2)=4S_(1)`

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