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InterviewSolution
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A particle starts oscillating simple harmonically from its equilibrium position then, the ratio of kinetic energy and potential energy of the particle at the time `T//12` is: `(T="time period")` |
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Answer» At,`t=(T)/(12),x A "sin" (2pi)/(T)xx(T)/(12)=A"sin"(pi)/(6)=(A)/(2)` so, KE`=(1)/(2)k(A^(2)-x^(2))=(3)/(4)xx(1)/(2)kA^(2)` and `PE=(1)/(2)kx^(2)=(1)/(4)xx(1)/(2)kA^(2)` `therefore (KE)/(PE)=(3)/(1)` |
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