1.

A particle starts with velocity u and moves with constant acceleration a .what is the nature of the graph between the time (t) and the displacement (x).(a) straight line(b) symmetric parabola(c) Asymmetric parabola(d) Rectangular hyperbola.

Answer»

Answer is (c) Asymmetric parabola

Here x = ut + (1/2)at2. It is of the form y = ax + bx2.

So the graph is a symmetric parabola



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