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                                    The initial velocity of a particle moving along a straight line is 10 m/s and its retardation is 2 ms-2. the distance moved by the particle in the fifth second of its motion is :(a) 1 m (b) 19 m(c) 50 m (d) 75 m | 
                            
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Answer»  Answer is (a) 1m x(nth) = u + 1/2a (2n-1) = 10 + ½ x(-2) (2 x 5-1) = (10 - 9)m = 1m.  | 
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