A particle strikes a horizontal smooth floor with a velocity u making an angle theta with the floor and rebounds with velocity v making an angle phiwith the floor. The coefficient of restitution between the particle and the floor is e.

A particle strikes a horizontal smooth floor with a velocity u making

1.	A particle strikes a horizontal smooth floor with a velocity u making an angle theta with the floor and rebounds with velocity v making an angle phiwith the floor. The coefficient of restitution between the particle and the floor is e.
Answer» The impulse delivered by the floor to the BODY is MU (1+e) sin `theta`. TAN `phi=e tan theta`. `v=usqrt(1-(1-e^2)sin^2 theta)` The ratio of the final kinetic energy to the initial kinetic energy is `cos^2 theta + e^2 sin^2 theta`. Answer :A::B::C::D

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A particle strikes a horizontal smooth floor with a velocity u making an angle theta with the floor and rebounds with velocity v making an angle phiwith the floor. The coefficient of restitution between the particle and the floor is e.

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