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A particle that carries a charge .-q. is placed at rest in uniform electric field 10N/C. It experiences a force and moves. In a certain time .t., it is observed to acquire a velocity 10 bat(i) - 10 hat(j) m/s. The given electric field intersects a surface of area 1 m^(2) in the x-z plane. Find the Electric flux through the surface. |
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Answer» SOLUTION :Force on charge `BAR(F)= q bar(E )` `therefore` particle MOVES opposite to `bar(E )" with " bar(V)` unit VECTOR in the direction of `bar(V ) " is " (bar(i))/(sqrt2) - (bar(j))/(sqrt2)` unit vector in the direction of `bar(E ) " is" (bar(i))/(sqrt2) - (bar(j))/(sqrt2)` `bar(E ) = 10 [(-i)/(sqrt2) + (j)/(sqrt2)]` ie `bar(A) = 1 xx bar(j)` Electric flux `phi = bar(E ).bar(A )= 5 sqrt2 Nm^(2)//C` |
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