1.

A particle travels in a circular path of radius 0.2 m with a constant kinetic energy of 4J . What is the net force on the particle?

Answer»

4N
16N
20N
40N

Solution :Because the PARTICLE travels ina a circular path with constant kinetic energy (which implies constant speed), the net force on the particle is the CENTRIPETAL force.
`F=(mv^(2))/(R)=(2((1)/(2)mv^(2)))/(r)=(2K)/(r)=(2(4J))/(0.2m)=40N`.


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