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A particle undergoes S.H.M. with a time period of 2 seconds. In how much time will it travel from its mean position to a displacement equal to half of its amplitude ? |
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Answer» Solution :We know that `T=(2pi)/omega=2(thereforeomega=pi)` When PARTICLE starts from MEAN position, `x=asin omegat` For `x=a/2` ` a/2=a sin omegat` therefore 1/2=sin omegat=sin PIT(there omega=pi)` ` therefore pit=pi/6` `thereforet=1/6sec` |
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