1.

A particle with charge 2.0 C movess through a uniform magnetic field. At one instant the velocity of the particle is (2.0hati+4.0hatj+6.0hatk) m//s and the magnetic force on the particle is (4.0hati-20hatj+12hatk) N. The x and y components of the magnetic fields are equal. What is vecB ?

Answer»


ANSWER :`VECB=(-3.0hati-3.0hatj-4.0hatk)T`


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