1.

A particle with charge Q, moving with a momentum p, enters a uniform magnetic field normally. The magnetic field has magnitude B and is confined to a region of width d, where d lt P/(BQ). The particle is deflected by an angle thetain crossing the field. Then

Answer»

<P>SIN `THETA=(BQd)/p`
`sin theta =p/(BQd)`
`sin theta =(Bp)/(Qd)`
`sin theta = (pd)/(BQ)`

Solution :A to D is part of circle with centre C and radius CD=r
mv=p=BQr
`r=p/(BQ)`
sin `theta=(ED)/(CD)=d/r=(BQd)/p`


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