A particular state of system is arrived at starting from a given state in two different ways `(1)` following reversible path and `(2)` irreversible path. Which of the following relations would be correct if the processes are isothermal ?A. `DeltaS_(rev)ne DeltaS_(irrev)`B. `Deltaq_(rev) = Deltaq_(irrev)`C. `DeltaS_(rev) = DeltaS_(irrev)=(Deltaq_(rev))/(T)`D. `DeltaS_(irrev)=(Deltaq_(irrev))/(T)ne DeltaS_(rev)`

A particular state of system is arrived at starting from a given state

1.	A particular state of system is arrived at starting from a given state in two different ways `(1)` following reversible path and `(2)` irreversible path. Which of the following relations would be correct if the processes are isothermal ?A. `DeltaS_(rev)ne DeltaS_(irrev)`B. `Deltaq_(rev) = Deltaq_(irrev)`C. `DeltaS_(rev) = DeltaS_(irrev)=(Deltaq_(rev))/(T)`D. `DeltaS_(irrev)=(Deltaq_(irrev))/(T)ne DeltaS_(rev)`
Answer» Correct Answer - B Since entropy is a state function, bence, `DeltaS_(rev)=DeltaS_(irrev)=(Deltaq_(rev))/(T)`

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