1.

A pendulam of length L and bob of mass M has a speing of force constant K connected a speing of force constsnt K connected horizontally to it at a distance h below is point of suspension. The rod is in equilibrium in vertical podition. The rod of length L. used for vertical suspension s rigid and massless. The frequency of vibration of the system for small values of theta is

Answer»

`(1)/(2piL)sqrt(gL+(kh)/(m))`
`(1)/(2piL)sqrt((mgL+k)/(m))`
`2pisqrt((KL^(2))/(mgL+kh))`
`(1)/(2piL)sqrt(gL+(kh^(2))/(m))`

Solution :`T=[mgL sintheta+kh^(2)THETA]`
Forsmall angle sin `theta ~~ theta`
`T=lalpha=-(mgL+kh^(2))theta`
`alpha=-(mgL+kh^(2))theta//mL^(2)`
`Sof=(1)/(2piL)sqrt(gL+(kh^(2))/(m))`


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