1.

A pendulum bob has a period 24s. Its velocity 4 s after it has passed the mean position is 6.28" cm s"^(-1). The amplitude of its motion is :

Answer»

12 cm
24 cm
48 cm
40 cm

Solution :Use `v=r omega cos omegat`.
`6.28=r""(2PI)/(24).cos((2pi)/(24).4)`
`IMPLIES""r=48` cm.
HENCE correct choice is ( c ).


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