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A pendulum bob of mass 5xx10^(-2) kg is raised to a height of 5xx10^(-2) m and then released. At the bottom of its swing it picks up a mass 10-kg and sticks to it. To what height the combined mass rise |
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Answer» 0.24 m `=sqrt(2gh)=sqrt(2xx10xx5xx10^(-2))=1 ms^(-1)` Now are conservation of momentum. `(5xx10^(-2)+10^(-3))V.=5xx10^(-2)xx1` `IMPLIES v.=(5xx10^(-2))/(5.1xx10^(-2))=(5)/(5.1)ms^(-1)` `:.` HEIGHT to which the combined mass rises is `h=(v^(2))/(2g)=((5)/(5.1))^(2)xx(1)/(2xx10)=0.48m` |
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