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A pendulum bob on a 2 m string is displaced `60^(@)` from the verticle and then released . What is the speed of the bob as it passes through the lowest point in its path?A. `sqrt2 m//s`B. `sqrt 9.8 m//s`C. `4.43 m//s`D. `1//sqrt2 m//s` |
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Answer» Correct Answer - C `v=sqrt(2gl(1- cos theta))` `=sqrt(2xx9.8xx2(1- cos 60^(@)))=4.43 m//s`. |
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