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A pendulum clock has an iron pendulum 1 m long `(alpha_("iron")=10^(-5) //^(@)C)` . If the temperature rises by `10^(@)C`, the clockA. will lose 8 seconds per dayB. will lose 4.32 seconds per dayC. will gain 8 seconds per dayD. will gain 4.32 second per day |
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Answer» Correct Answer - B `(DeltaT)/(T_(0))=1/2 alpha.Delta theta` In one day the change in time `=86400xx(DeltaT)/(T_(0))` `=86,400xx1/2xx10^(-5)xx10=4.32 sec `(lose) |
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