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A pendulum clock runs fast by `5` seconds per day at `20^(0)c` and goes slow by `10` seconds per day at `35^(0)C`. It shows correct time at a temperature ofA. `27.5^(0)C`B. `25.^(0)C`C. `30.^(0)C`D. `33.^(0)C` |
Answer» Correct Answer - B `(1)/(2)alpha(35-t)xx86400=10----(1)` `(1)/(2)alpha(t-20)xx86400=5----(2)` Solving `1` and `2` |
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