A pendulum is first vibrated on the surface of earth. Its period is T. It is then taken to the surface of moon where acceleration due to gravity is 1/6th of that on earth. Its period will be :

A pendulum is first vibrated on the surface of earth. Its period is T.

1.	A pendulum is first vibrated on the surface of earth. Its period is T. It is then taken to the surface of moon where acceleration due to gravity is 1/6th of that on earth. Its period will be :
Answer» `(T)/(6)` `(T)/(3)` `(T)/(sqrt(3))` `Tsqrt(6)` SOLUTION :`(T_(2))/(T_(1))=sqrt((a_(1))/(a_(2)))` `:. T_(2)=T sqrt((g)/(g//6))=T sqrt(6)` Thus CORRECT choice is (d).

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A pendulum is first vibrated on the surface of earth. Its period is T. It is then taken to the surface of moon where acceleration due to gravity is 1/6th of that on earth. Its period will be :

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