1.

A pendulum suspended from ceiling of a train has a time period T, when the train is at rest. When the train is accelerating with uniform acceleration 'a', the period of oscillation will

Answer»

Decrease
Increase
Remains UNAFFECTED
Becomes infinite.

Solution :When TRAIN is at rest `T=2pi sqrt((L)/(g))`.
When train accelerates then net acceleration is
`a_("net")=sqrt(g^(2)+a^(2))gt g`
`:. T.=2pi sqrt((l)/(sqrt(g^(2)+a^(2))))`
Sotime PERIOD decreases.
Correct choice is (a).


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