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A perfect gas at 27^(@)C is heated at constant pressure so as to double its volume. The increase in temperature of the gas will be: |
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Answer» `600^(@)C` `V prop T` Here `(V_(1))/(V_(2))=(T_(1))/(T_(2))"…..(i)"` Accoring to qestion, `V_(1)=V" then "V_(2)=2V and T_(1)=300 K` `therefore (1)/(2) =(300)/(T_(2))` `T_(2)=600 K` `T_(2)=327^(@)C` So, `Delta T=327 -27 =300^(@)C` So, correct choice is (d). |
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