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A perfect gas goes from a state A to another state B by absorbing 8 × 105 J of heat and doing 6.5 × 105 J of external work. It is now transferred between the same two states in another process in which it absorbs 105 J of heat. In the second processA. Work done on the gas is `0.5xx10^5J`B. Work done by gas is `0.5xx10^5J`C. Work done on gas is `10^5J`D. Work done by gas is `10^5J` |
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Answer» Correct Answer - A Process 1: `DeltaQ=DeltaU+DeltaW` `8xx10^5=DeltaU+6.5xx10^5` `DeltaU=1.5xx10^5J` Process 2: `DeltaQ=DeltaU+DeltaW` `10^5=1.5xx10^5+DeltaWimpliesDeltaW=-0.5xx10^5J` |
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