A persin moves 30 m north, then 20 m east and finally 30sqrt(2) m south-west. The displacement from the original position is :

A persin moves 30 m north, then 20 m east and finally 30sqrt(2) m sout

1.	A persin moves 30 m north, then 20 m east and finally 30sqrt(2) m south-west. The displacement from the original position is :
Answer» 14 m south-WEST 10 m west 28 m south 15 m east Solution :`VEC(S)=30hatj,vec(S_(2))=20hati` `vec(S_(3))=-30sqrt(2)(cos45hati + sin45hatj)` `vec(S)=vec(S_(1)) + vec(S_(2)) + vec(S_(3))=30hatj + 20hati -30hati-30hatj=-10 hati` Hence RESULTANT displacement is 10 m (west).

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A persin moves 30 m north, then 20 m east and finally 30sqrt(2) m south-west. The displacement from the original position is :

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