1.

A person adds 1*71 gram of sugar (C_(12)H_(22)O_(11)) in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar - 342)

Answer»

`3*6xx10^(22)`
`7*2XX10^(21)`
`0*05`
`6*6xx10^(22)`

SOLUTION :Moles of sugar added `= (1*71)/(342) = 5xx10^(-3)`
CARBON atoms added
`=12xx5xx10^(-3)xx6*02xx10^(23)`
`= 3.61xx10^(22)`


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