InterviewSolution
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InterviewSolution
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A person can throw a stone to a maximum height of h meter. The maximum distance to which he can throw the stone is:A. `h`B. `h//2`C. `2h`D. `3h` |
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Answer» Correct Answer - c Height H is given by `H=(u^(2) sin^(2) theta)/(2g)` When `theta =90^(@), H=H_(max)=(u^(2))/(2g)=h` Range is given by: `R=(u^(2) sin 2theta)/g` Now, `R_(max)=(u^(2))/g (When theta=45^(@))=2h` |
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