A person draws a card from a well shuffled pack of 52 playing cards. Replaces it and shuffles the pack. He continues doing so until he draws as pade. The chance that he fails first two times isA. `(1)/(16)`B. `(9)/(16)`C. `(9)/(64)`D. `(1)/(64)`

A person draws a card from a well shuffled pack of 52 playing cards. R

1.	A person draws a card from a well shuffled pack of 52 playing cards. Replaces it and shuffles the pack. He continues doing so until he draws as pade. The chance that he fails first two times isA. `(1)/(16)`B. `(9)/(16)`C. `(9)/(64)`D. `(1)/(64)`
Answer» Correct Answer - B Let `A_(i)` be the event that the person fails in `i^(th)` draw. Then, `P(A_(i))=1-(13)/(52)=(3)/(4), i=1,2,3,..` `therefore` Required Probability `=P(A_(1) cap A_(2))=P(A_(1))P(A_(2))` `implies` Required probability `=(3)/(4)xx(3)/(4)=(9)/(16)`

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A person draws a card from a well shuffled pack of 52 playing cards. Replaces it and shuffles the pack. He continues doing so until he draws as pade. The chance that he fails first two times isA. `(1)/(16)`B. `(9)/(16)`C. `(9)/(64)`D. `(1)/(64)`

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