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A person facing north walks 3km turn left and walk 4km again walks 3km after turning right then turns right and 12km what is the displacement from the starting point and which direction he is facing ? |
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Answer» Here is ur answer mate Since a person is moving towards North for 3km
therefore ↑North - 3km Now the person turns to walk 4km further
therefore ↑North - 3km and ←West - 4km Now the person walks 3km after turning right
therefore ↑North - 3km + 3km = 6km and ←West - 4km In the end the person turns right again and moves forward the 12KM in EAST direction
Therefore ↑North - 6km and ←West - (4km - 12km) = -8KM Here we get West direction in negative therefore we will replace it by East and -8km by its ADDITIVE inverse i.e 8km Therefore ↑North - 6km → East - 8km Here a formation of a right triangle can be observed.... Where 8km and 6m are lengths of its legs Therefore by Applying Pythagoras theorem (Displacement)² = (Northen Displacement)² + (Eastern Displacement)² or (Displacement)² = (6km)² + (8km)² = 36km² + 64km² = 100km² or Displacement = √(100km²) = 10km |
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