A person invests Rs. 10,000 at 5% per annum compounded annually for tw

1.	A person invests Rs. 10,000 at 5% per annum compounded annually for two years. Then he invests thematurity amount for one year at 8% per-annum compounded half yearly. What is the total amount he willreceive at the end of three years?
Answer» Step-by-step explanation: It is given that Principal(P) = 10,000 PERIOD (T)= 1 year SUM amount (A)= 11200 Rate of interest =? (i) We know that Interest (I)= 11200- 10000= 1200 So the rate of interest R= (1×100)/(P×T) Substituting the values R= (1200×100)/(1000×1) So we GET R= 12% p.a Therefore, the rate of interest PER annum is 12% p.a (ii) We know that Period (T)= 2 years Rate of interest (R) = 12% p.a. Here A =P(1+R/100) 1 Substituting the values A = 10000(1+12/100) 2 By further calculation A= 10000(28/25) 2 We can write it as A= 10000×28/25×28/25 So we get A=16×28×28 A=12544 Therefore, the amount at the end of the SECOND year is 12544.

A person invests Rs. 10,000 at 5% per annum compounded annually for two years. Then he invests thematurity amount for one year at 8% per-annum compounded half yearly. What is the total amount he willreceive at the end of three years?

Answer»

Step-by-step explanation:

It is given that

Principal(P) = 10,000

PERIOD (T)= 1 year

SUM amount (A)= 11200

Rate of interest =?

(i) We know that

Interest (I)= 11200- 10000= 1200

So the rate of interest

R= (1×100)/(P×T)

Substituting the values

R= (1200×100)/(1000×1)

So we GET

R= 12% p.a

Therefore, the rate of interest PER annum is 12% p.a

(ii) We know that

Period (T)= 2 years

Rate of interest (R) = 12% p.a.

Here

A =P(1+R/100)

Substituting the values

A = 10000(1+12/100)

By further calculation

A= 10000(28/25)

We can write it as

A= 10000×28/25×28/25

So we get

A=16×28×28

A=12544

Therefore, the amount at the end of the SECOND year is 12544.