1.

A person sitting firmly over a rotating stool has his arms stretched. If he folds his arms, his angular momentum about the axis of the rotation :

Answer»

Increases
Decreases
Remains unchanged
Doubles.

Solution :When the person fold his arm then TORQUE is zero. SINCE `tau=(DL)/(dt)=0impliesL` = constant
i.e. ANGULAR momentum remains CONST.


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