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A person starts from a point P and walks 1 kmalong a straight line and then turns to hisright and walks straight for 2 km. After that,he turns to his left and walks for 3 km toreach a point Q. What is the straight linedistance of the point Q from the point P ? |
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Answer» Answer: Correct option is B 15 km The movement of the PERSON are as shown in fig. Clearly AB = 3 km BC=3AB=(3×3)KM=9KM CD=5AB=(5×3)KM=15KM Draw AE ⊥ CD. Then CE = AB = 3 km and AE = BC = 9Km DE = (CD-CE)=(15-3)Km = 12 Km. In Δ AED, AD 2 =AE 2 +DE 2
= AD=( 2 +(12) 2
)km=15km ∴ Required distance = AD = 15 Km. |
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