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A Person Travels From X To Y At A Speed Of 40km/h And Returns By Increasing His Speed 50%. What Is His Average Speed For Both The Trips?

Answer»

Speed of PERSON from x to y =40 km/h 

Speed of person from y to x =(40x150)/100 = 60km/h 

Since the distance travelled is same 

THEREFORE, Average Speed = (2x40x60)/40+60 = 48km/h.

Speed of person from x to y =40 km/h 

Speed of person from y to x =(40x150)/100 = 60km/h 

Since the distance travelled is same 

Therefore, Average Speed = (2x40x60)/40+60 = 48km/h.



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