InterviewSolution
Saved Bookmarks
| 1. |
A Person Travels From X To Y At A Speed Of 40km/h And Returns By Increasing His Speed 50%. What Is His Average Speed For Both The Trips? |
|
Answer» Speed of PERSON from x to y =40 km/h Speed of person from y to x =(40x150)/100 = 60km/h Since the distance travelled is same THEREFORE, Average Speed = (2x40x60)/40+60 = 48km/h. Speed of person from x to y =40 km/h Speed of person from y to x =(40x150)/100 = 60km/h Since the distance travelled is same Therefore, Average Speed = (2x40x60)/40+60 = 48km/h. |
|