1.

In How Many Different Ways Can Four Books A, B, C And D Be Arranged One Above Another In A Vertical Order Such That The Books A And B Are Never In Continuous Position?

Answer»

The NUMBER of arrangement in which A and B are not TOGETHER 

= Total number of ARRANGEMENTS 

= Number of arrangements in which A and B are together =4!-3!x2! = 24-12 =12.

The number of arrangement in which A and B are not together 

= Total number of arrangements 

= Number of arrangements in which A and B are together =4!-3!x2! = 24-12 =12.



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