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In How Many Different Ways Can Four Books A, B, C And D Be Arranged One Above Another In A Vertical Order Such That The Books A And B Are Never In Continuous Position? |
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Answer» The NUMBER of arrangement in which A and B are not TOGETHER = Total number of ARRANGEMENTS = Number of arrangements in which A and B are together =4!-3!x2! = 24-12 =12. The number of arrangement in which A and B are not together = Total number of arrangements = Number of arrangements in which A and B are together =4!-3!x2! = 24-12 =12. |
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