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A person tries to broadcast with the same antenna both the signals at 10^(7) Hz and 10^(6) Hz. If the reciver at some distance has to receive an equal strenght for both the frequencies, then the broadcaster has to approximately increase the signal strenght at 10^(6) Hz to 10^(7) Hz by |
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Answer» `(1)/(10)"times"` or `P prop V^2`, where, v = frequency so`P_1/P_2 = v_1^2/v_2^2` GIVEN, `v_1 = 10^7 Hz, v_2 = 10^6 Hz` `P_1/P_2 = ((10^7)/(10^6))^2 = 100` `rArrP_1 = 100P_2` Power of frequency `10^7` is 100 times GREATER than `10^6`. So, sighnal stregth of frequency `10^6` Hz need to be increased by 100 times for equal strength at some distance . |
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