1.

A person tries to broadcast with the same antenna both the signals at 10^(7) Hz and 10^(6) Hz. If the reciver at some distance has to receive an equal strenght for both the frequencies, then the broadcaster has to approximately increase the signal strenght at 10^(6) Hz to 10^(7) Hz by

Answer»

`(1)/(10)"times"`
10 times
100 times
`(1)/(100)"times"`

Solution :Power of signal radiated by an antenna `P prop 1/LAMBDA^2`. where, `lambda` = wavelength of signal
or `P prop V^2`, where, v = frequency
so`P_1/P_2 = v_1^2/v_2^2`
GIVEN, `v_1 = 10^7 Hz, v_2 = 10^6 Hz`
`P_1/P_2 = ((10^7)/(10^6))^2 = 100`
`rArrP_1 = 100P_2`
Power of frequency `10^7` is 100 times GREATER than `10^6`. So, sighnal stregth of frequency `10^6` Hz need to be increased by 100 times for equal strength at some distance .


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