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A person uses a lens of power `+3D` to normalise vision. Near point of hypermetropic eye isA. `1m`B. `1.66m`C. `2m`D. `0.66m` |
Answer» Correct Answer - A Focal length of the lens`f=(100)/(3)` By lens formula `(1)/(f)=(1)/(v)-(1)/(u)` `implies(1)/(+100//3)=(1)/(v)-(1)/(-25)impliesv=-100cm=-1m` |
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