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A person walks up a stationary excalator in time tl. If he remains stationary on the escalator, then it can take him up in time t_(2). How much time would it take him to walk up the moving escalator? |
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Answer» Solution :Let L be the length of ascalator. SPEED of man w.r.t esacalator is `v_(me)=(L)/(t_(1))`. Speed of escalator `v_(E)=(L)/(t_(2))` Speed of man with respect to GROUND would be `v_(m)+v_(me)+v_(e)=L((1)/(t_(1))+(1)/(t_(2)))` `:.` The desired time is `t=(L)/(v_(m))=(t_(1)t_(2))/(t_(1)+t_(2))` |
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