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A person with vibrating tuning fork of frequency 338 Hz Is moving towards a vertical wall with a speed of 2 ms^(-1) . Velocity of sound in air is 340 ms^(-1) . The number of beats by that person per second is : |
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Answer» 2 `v. = ((v+ u_(0))/(v - u_(0))) ` v = `((340 + 2)/(340 -2)) 338 ` = 342 Hz. `THEREFORE` No. of beats heard by the person= v. - v = 342 - 338 = 4 Hz. So CORRECT choice is b. |
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