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A petrol engine consumes 20 kg of petrol per hour. The calorific value of the fuel is1 xx 10^(7) cal/kg. The power of the engine is 84 kilowatt. Calculate the efficiency of the engine. |
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Answer» `36 %` `m_(f) = 20/(60 xx 60) kg//s` Heat released DUE to the combustion of fuel, `Q = m_(f) xx ` calorific value of the fuel ` = 20/(60 xx 60) xx 1 xx 10^(7)` ` = 10^(6)/18 " cal/s" = 10^(6)/18 xx 4.2 " joule /s " = 700/3 ` kW Power produced by the engine , `W = 84 kW` ` :. ` EFFECIENCY of the engine ` = W/Q xx 100 = 84/(700//3) xx 100 = 36% ` |
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