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A photocell is placed at 1 m distance from light source when distance is changed to (1)/(2)m no.of photoelectron emitted from cathode will come |
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Answer» become 2 times `THEREFORE I prop (1)/(d^(2)) therefore (I_(2))/(I_(1))=((d_(1))/(d_(2)))^(2)` From `d_(2)=(d_(1))/(2)` `(I_(2))/(I_(1))=(2)^(2)=4` intensity becomes four times. |
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