InterviewSolution
Saved Bookmarks
| 1. |
A photon and electron have got same de Broglie wavelength. Which has greater total energy ? |
|
Answer» SOLUTION :Energy of a PHOTON = `E_1 = hv=(hc)/LAMBDA` For electron `lambda = h/(MV)=h/(lambda v)` Energy of electron `E_2 = mc^2 = (hc^2)/(lambda v)` `E_1/E_2 = (hc)/lambda XX (hv)/(hc^2)=v/c` |
|