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A photon and electron have got same de Broglie wavelength. Which has greater total energy ?

Answer»

SOLUTION :Energy of a PHOTON = `E_1 = hv=(hc)/LAMBDA`
For electron `lambda = h/(MV)=h/(lambda v)`
Energy of electron `E_2 = mc^2 = (hc^2)/(lambda v)`
`E_1/E_2 = (hc)/lambda XX (hv)/(hc^2)=v/c`


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