1.

A photon has same wavelength as the de Broglie wavelength of electrons. Given C=speed of light, v=speed of electron. Which of the followitg relation is correct? [Here E_e= kinetic energy of electron, E_(ph)= energy of photon, P_e= momentum of electron and P_(ph)= momentum of photon]

Answer»

`(E_e)/(E_(ph))=(2C)/(v)`
`(E_e)/(E_(ph))=(v)/(2C)`
`(P_e)/(P_(ph))=(2C)/(v)`
`(P_e)/(P_(ph))=(C)/(v)`

Solution :`lamda_(ph)=lamda_e`
`(h)/(p_(ph))=(h)/(p_e)`
`(E_e)/( C)=(2E_e)/(v)`
`(E_e)/(E_(ph))=(v)/(2C)`


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