1.

A photon of radiation of wavelength 4000 Å has an energy E. The wavelength of photon of radiation having energy 0.5 E will be

Answer»

2000 Å
8000 Å
4000 Å
6000 Å

Solution :`E=hv=hc/(lamda),(E_(1))/(E_(2))=(lamda_(2))/(lamda_(1)),E/(0.5E)=(lamda_(2))/4000` or `lamda_(2)=8000Å`


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