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| 1. |
A photon of radiation of wavelength 4000 Å has an energy E. The wavelength of photon of radiation having energy 0.5 E will be |
| Answer» Solution :`E=hv=hc/(lamda),(E_(1))/(E_(2))=(lamda_(2))/(lamda_(1)),E/(0.5E)=(lamda_(2))/4000` or `lamda_(2)=8000Å` | |