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A photon of radiationof wavelength 600 nm has an energy E. The wavelength of photon of radiation having energy 0.25 E is

Answer»

600 NM
2400 nm
150 nm
300 nm

Solution :`(E_(1))/(E_(2))=(lamda_(2))/(lamda_(1))impliesE/0.25E=(lamda_(2))/600`
`:.lamda_(2)=600/0.25=(lamda_(2))/600`
`:.lamda_(2)=600/0.25=2400 nm`


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