A physical quantity P is related to four observables a, b, c and d as `P=a^(3)b^(2)//sqrtcd`. The percentage errors in the measurements of a, b, c and d are `1%, 3% 4%` and `2%` respectively. What is the percentage error in the quantity P? If the value of P calculated using this formula turns out to be `3.763`, to what value should you round off the result?

A physical quantity P is related to four observables a, b, c and d as

1.	A physical quantity P is related to four observables a, b, c and d as `P=a^(3)b^(2)//sqrtcd`. The percentage errors in the measurements of a, b, c and d are `1%, 3% 4%` and `2%` respectively. What is the percentage error in the quantity P? If the value of P calculated using this formula turns out to be `3.763`, to what value should you round off the result?
Answer» Correct Answer - `13%,3.8`

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A physical quantity P is related to four observables a, b, c and d as `P=a^(3)b^(2)//sqrtcd`. The percentage errors in the measurements of a, b, c and d are `1%, 3% 4%` and `2%` respectively. What is the percentage error in the quantity P? If the value of P calculated using this formula turns out to be `3.763`, to what value should you round off the result?